An electric bulb, a capacitor, a battery, and | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When the switch is turned on, the capacitor begins to charge. Initially, the charge on the capacitor is $0$, so the potential difference across it

Vedclass · Accepted Answer

Sharply rises initially and then gradually decreases

Vedclass · Answer

(C) When the switch is turned on, the capacitor begins to charge. Initially, the charge on the capacitor is $0$, so the potential difference across it is $0 \ V$. Consequently, the entire battery voltage appears across the bulb, causing it to glow with maximum intensity.As the capacitor charges, the potential difference across it $(V_c = q/C)$ increases over time. According to Kirchhoff's voltage law, the voltage across the bulb $(V_b)$ is given by $V_b = V_{battery} - V_c$. As $V_c$ increases, $V_b$ decreases.Therefore, the intensity of the light, which depends on the power dissipated by the bulb $(P = V_b^2 / R)$, will be maximum at the start and will gradually decrease as the capacitor becomes fully charged.

An electric bulb, a capacitor, a battery, and a switch are all connected in series in a circuit. How does the intensity of light vary when the switch is turned on?

Similar Questions

$A$ $2500 \,\mu F$ capacitor is charged through a $1 \,k\Omega$ resistor by a $12 \,V$ d.c. source. The voltage across the capacitor after $5 \,s$ is ..... $V$.

In the given circuit, the potential difference across the plates of the capacitor $C$ in steady state is (in $V$)

$A$ charged capacitor is allowed to discharge through a resistance of $2 \, \Omega$ by closing the switch $S$ at the instant $t = 0$. At time $t = \ln 2 \, \mu s$,the reading of the ammeter falls to half of its initial value. The resistance of the ammeter is equal to:

In the circuit shown in the figure,$R = \sqrt{\frac{L}{C}}$. Switch $S$ is closed at time $t = 0$. The current through $C$ and $L$ would be equal after a time $t$ equal to

$A$ $4 \mu F$ capacitor and a resistance of $2.5 \, M\Omega$ are in series with a $12 \, V$ battery. Find the time after which the potential difference across the capacitor is $3$ times the potential difference across the resistor. (Given $\ln(2) = 0.693$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module