An electric bulb illuminates a plane surface. The intensity of illumination on the surface at a point $2 \ m$ away from the bulb is $5 \times 10^{-4} \ phot$ $(lumen/cm^2)$. The line joining the bulb to the point makes an angle of $60^{\circ}$ with the normal to the surface. The intensity of the bulb in candela is

  • A
    $40\sqrt{3}$
  • B
    $40$
  • C
    $20$
  • D
    $40 \times 10^{-4}$

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