An electric dipole of length 4 cm is placed | vedclass

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Question

(B) The torque acting on an electric dipole is given by the formula: $	au = pE \sin 	heta$.Given $	au = 20 \sqrt{3} \ Nm$ and $	heta = 30^{\circ}$

Vedclass · Accepted Answer

$-60$

Vedclass · Answer

(B) The torque acting on an electric dipole is given by the formula: $	au = pE \sin 	heta$.Given $	au = 20 \sqrt{3} \ Nm$ and $	heta = 30^{\circ}$,we have:$20 \sqrt{3} = pE \sin 30^{\circ} = pE 	imes \frac{1}{2}$.Therefore,$pE = 40 \sqrt{3} \ Nm$.The potential energy $U$ of an electric dipole in an external electric field is given by: $U = -pE \cos 	heta$.Substituting the values: $U = -(40 \sqrt{3}) \cos 30^{\circ} = -(40 \sqrt{3}) 	imes \frac{\sqrt{3}}{2}$.$U = -40 	imes \frac{3}{2} = -20 	imes 3 = -60 \ J$.

An electric dipole of length $4 \ cm$ is placed with its axis making an angle of $30^{\circ}$ to a uniform electric field of $10^6 \ N/C$. If it experiences a torque of $20 \sqrt{3} \ Nm$,then the potential energy of the dipole is: (in $J$)

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