An electric dipole of moment overrightarrow{p | vedclass

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Question

(D) The work done $W$ in rotating an electric dipole in an external electric field is given by the formula:$W = pE(\cos 	heta_1 - \cos 	heta_2)$Here

Vedclass · Accepted Answer

Zero

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(D) The work done $W$ in rotating an electric dipole in an external electric field is given by the formula:$W = pE(\cos 	heta_1 - \cos 	heta_2)$Here,the initial angle $	heta_1 = 90^\circ$ (since it is placed normal to the field).The dipole is deflected through an angle of $180^\circ$,so the final angle $	heta_2 = 90^\circ + 180^\circ = 270^\circ$.Substituting these values:$W = pE(\cos 90^\circ - \cos 270^\circ)$Since $\cos 90^\circ = 0$ and $\cos 270^\circ = 0$,$W = pE(0 - 0) = 0$.Therefore,the work done is zero.

An electric dipole of moment $\overrightarrow{p}$ is placed normal to the lines of force of electric intensity $\overrightarrow{E}$. The work done in deflecting it through an angle of $180^\circ$ is:

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