An electric lamp is marked $100 \, W, 220 \, V$. It is used for $5$ hours daily. Calculate: $(i)$ its resistance while glowing. $(ii)$ energy consumed in $kWh$ per day.

(N/A) $(i)$ The resistance $R$ of the lamp is calculated using the formula $R = \frac{V^2}{P}$. Substituting the given values: $R = \frac{(220)^2}{100} = \frac{48400}{100} = 484 \, \Omega$.
$(ii)$ The energy consumed $E$ is calculated using the formula $E = P \times t$. Given $P = 100 \, W$ and $t = 5 \, h$,we get $E = 100 \, W \times 5 \, h = 500 \, Wh$. Converting to $kWh$,$E = \frac{500}{1000} \, kWh = 0.5 \, kWh$.