An electrical circuit consists of ten 100 ,Om | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The total resistance $R_{eq}$ of the circuit is given by Ohm's law: $R_{eq} = \frac{V}{I} = \frac{100 \,V}{2.5 \,A} = 40 \,\Omega$.Each resistor h

Vedclass · Accepted Answer

$5, 5$

Vedclass · Answer

(B) The total resistance $R_{eq}$ of the circuit is given by Ohm's law: $R_{eq} = \frac{V}{I} = \frac{100 \,V}{2.5 \,A} = 40 \,\Omega$.Each resistor has a resistance $R = 100 \,\Omega$. The equivalent resistance of $n_1$ resistors in parallel is $R_1 = \frac{R}{n_1} = \frac{100}{n_1}$.The equivalent resistance of $n_2$ resistors in parallel is $R_2 = \frac{R}{n_2} = \frac{100}{n_2}$.Since the two groups are in series,$R_{eq} = R_1 + R_2 = \frac{100}{n_1} + \frac{100}{n_2} = 40$.Dividing by $20$,we get $\frac{5}{n_1} + \frac{5}{n_2} = 2$.Given that $n_1 + n_2 = 10$,we test the options:For option $B$,$n_1 = 5$ and $n_2 = 5$: $\frac{5}{5} + \frac{5}{5} = 1 + 1 = 2$. This satisfies the equation.Thus,the correct values are $n_1 = 5$ and $n_2 = 5$.

Similar Questions

The magnitude and direction of the current in the circuit shown will be

What is called earthing? Give the importance of earthing in electrical wiring.

In the figure,the current through the $3\,\Omega$ resistor is $0.8\,A$. Then,the potential drop across the $4\,\Omega$ resistor is ........... $V$.

In the given circuit,the current passing through the $12\, \Omega$ resistor is............ $A$.

The ratio of powers dissipated respectively in $R$ and $3R$,as shown in the figure,is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module