An electrochemical cell is set up as follows: | vedclass

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(A) The $E.M.F.$ of a concentration cell is given by $E_{cell} = \frac{0.0591}{n} \log \frac{[H^+]_{cathode}}{[H^+]_{anode}}$. Since $HCl$ is a strong

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The $pH$ of $0.1 \, M \, HCl$ and $0.1 \, M$ acetic acid is not the same.

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(A) The $E.M.F.$ of a concentration cell is given by $E_{cell} = \frac{0.0591}{n} \log \frac{[H^+]_{cathode}}{[H^+]_{anode}}$. Since $HCl$ is a strong acid,it dissociates completely,whereas $CH_3COOH$ is a weak acid and dissociates partially. Therefore,the concentration of $H^+$ ions in both compartments is different,leading to different $pH$ values. As a result,the $E.M.F.$ of the cell is not zero.

An electrochemical cell is set up as follows: $Pt(H_2, 1 \, atm) | 0.1 \, M \, HCl || 0.1 \, M \, CH_3COOH | (H_2, 1 \, atm) Pt$. The $E.M.F.$ of this cell will not be zero because:

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