An electron (mass = 9.1 times 10^{-31} kg; c | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) For no deflection in mutually perpendicular electric and magnetic fields,the velocity $v$ of the electron is given by $v = \frac{E}{B}$.Substituti

Vedclass · Accepted Answer

$0.45$

Vedclass · Answer

(C) For no deflection in mutually perpendicular electric and magnetic fields,the velocity $v$ of the electron is given by $v = \frac{E}{B}$.Substituting the given values: $v = \frac{3.2 	imes 10^5}{2 	imes 10^{-3}} = 1.6 	imes 10^8 \ m/s$.When the electric field is removed,the electron moves in a circular path due to the magnetic force acting as the centripetal force.The radius $r$ of the path is given by $r = \frac{mv}{qB}$.Substituting the values: $r = \frac{9.1 	imes 10^{-31} 	imes 1.6 	imes 10^8}{1.6 	imes 10^{-19} 	imes 2 	imes 10^{-3}} = \frac{9.1 	imes 10^{-23}}{3.2 	imes 10^{-22}} = 0.45 \ m$.

Similar Questions

Identify the blank spaces $a, b, c$ and $d$ given in the following table and select the correct answer.
| Organism | Type | Product |
| :--- | :--- | :--- |
| $a$ | $b$ | Cyclosporin-$A$ |
| $c$ | Bacterium | Butyric acid |
| $d$ | Bacterium | Lactic acid |

If $y = \cos^{-1}\left(\frac{a^2-x^2}{a^2+x^2}\right) + \sin^{-1}\left(\frac{2ax}{a^2+x^2}\right)$, then $\frac{dy}{dx}$ is equal to

How many moles of $KMnO_4$ are required to oxidize $1 \ mol$ of $FeC_2O_4$ in an acidic medium?

The arithmetic mean of a set of observations is $\bar{X}$. If each observation is divided by $\alpha$ and then increased by $10$,then the mean of the new series is:

In the following circuit,the current flowing through the $1 \, k\Omega$ resistor is ..... $mA$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module