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(A) The de-Broglie wavelength is given by $\lambda = \frac{h}{mv}$.Case $(i)$: The electron is moving opposite to the electric field. Since the electr

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Decreasing, remain same

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(A) The de-Broglie wavelength is given by $\lambda = \frac{h}{mv}$.Case $(i)$: The electron is moving opposite to the electric field. Since the electron is negatively charged, it experiences a force in the direction of the electric field, which accelerates it. As the velocity $v$ increases, the de-Broglie wavelength $\lambda$ decreases.Case $(ii)$: The electron is moving perpendicular to a magnetic field. The magnetic force acts perpendicular to the velocity, changing the direction of motion but not the magnitude of the velocity $v$. Since the speed $v$ remains constant, the de-Broglie wavelength $\lambda$ remains the same.

An electron is moving through a field. It is moving $(i)$ opposite to an electric field and $(ii)$ perpendicular to a magnetic field as shown. For each situation, determine the de-Broglie wavelength of the electron:

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Choose the only correct statement out of the following:

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