An element P has atomic number 56. What will | vedclass

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(B) The element $P$ with atomic number $56$ is Barium $(Ba)$,which belongs to Group $2$ of the periodic table.Elements in Group $2$ have $2$ valence e

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$PX_2$

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(B) The element $P$ with atomic number $56$ is Barium $(Ba)$,which belongs to Group $2$ of the periodic table.Elements in Group $2$ have $2$ valence electrons and tend to lose these electrons to form a stable cation with a $+2$ charge $(P^{2+})$.Halogens $(X)$ belong to Group $17$ and gain one electron to form an anion with a $-1$ charge $(X^-)$.To maintain electrical neutrality,one $P^{2+}$ ion combines with two $X^-$ ions.Therefore,the formula of the halide is $PX_2$.

An element $P$ has atomic number $56$. What will be the formula of its halide?

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