An element P has atomic number 56. What will | vedclass

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(B) The element $P$ with atomic number $56$ is Barium $(Ba)$,which belongs to Group $2$ of the periodic table.Group $2$ elements have $2$ valence elec

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$PX_2$

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(B) The element $P$ with atomic number $56$ is Barium $(Ba)$,which belongs to Group $2$ of the periodic table.Group $2$ elements have $2$ valence electrons and tend to lose these electrons to form a cation with a charge of $+2$,i.e.,$P^{2+}$.Halogens $(X)$ belong to Group $17$ and gain $1$ electron to form an anion with a charge of $-1$,i.e.,$X^-$.To form a neutral compound,one $P^{2+}$ ion combines with two $X^-$ ions.Therefore,the formula of the halide is $PX_2$.

An element $P$ has atomic number $56$. What will be the formula of its halide?

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