An element $E$ has an ionisation enthalpy value of $374 \ kJ \ mol^{-1}$. $E$ reacts with elements $A, B, C$ and $D$ with electron gain enthalpy values of $-328, -349, -325$ and $-295 \ kJ \ mol^{-1}$,respectively. The correct order of the products $EA, EB, EC$ and $ED$ in terms of ionic character is $:$

  • A
    $EB > EA > EC > ED$
  • B
    $ED > EC > EA > EB$
  • C
    $EA > EB > EC > ED$
  • D
    $ED > EC > EB > EA$

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Similar Questions

Match List-$I$ with List-$II$.
List-$I$ (Elements)List-$II$ (Properties)
$A. Cl, S$$I. \text{Elements with highest electronegativity}$
$B. Ge, As$$II. \text{Elements with largest atomic size}$
$C. Fr, Ra$$III. \text{Elements which show properties of both metals and non-metals}$
$D. F, O$$IV. \text{Elements with highest negative electron gain enthalpy}$

Choose the correct answer from the options given below:

Which of the following properties does not depend on periodicity?

Based on the provided periodic table segment,identify the incorrect statement.

Difficult
View Solution

Given below are two statements:
Statement-$I$: The correct order in terms of atomic/ionic radii is $Al > Mg > Mg^{2+} > Al^{3+}$.
Statement-$II$: The correct order in terms of the magnitude of electron gain enthalpy is $Cl > Br > S > O$.
In the light of the above statements, choose the correct answer from the options given below:

To which block do the elements with the following outer electronic configurations belong?
$(i)$ $6s^2 4f^3$
$(ii)$ $3s^2 3p^4$
$(iii)$ $3s^1$
$(iv)$ $3d^2 4s^2$

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