An element of group $2$ forms a covalent oxide which is amphoteric in nature and dissolves in water to give an amphoteric hydroxide. Identify the element and write chemical reactions of the hydroxide of the element with an alkali and an acid.

(N/A) In group $2$,$Be$ is the only element that forms a covalent oxide $BeO$,which is amphoteric in nature. The other elements of this group form ionic oxides which are basic in nature. $BeO$ reacts with water to form $Be(OH)_{2}$,which is an amphoteric hydroxide.
$BeO + H_{2}O \rightarrow Be(OH)_{2}$
$Be(OH)_{2}$ is amphoteric,meaning it reacts with both acids and bases.
Reaction with an alkali $(NaOH)$:
$2 NaOH_{(aq)} + Be(OH)_{2(s)} \rightarrow Na_{2}[Be(OH)_{4}]_{(aq)}$
(Sodium tetrahydroxoberyllate)
Reaction with an acid $(H_{2}SO_{4})$:
$Be(OH)_{2(s)} + H_{2}SO_{4(aq)} \rightarrow BeSO_{4(aq)} + 2 H_{2}O_{(l)}$
(Beryllium sulphate)