An element with atomic mass 100 has a bcc str | vedclass

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(B) The density of a crystal is given by the formula: $ho = \frac{n 	imes M}{N_A 	imes a^3} \, g \, cm^{-3}$.For a $bcc$ structure,the number of a

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$5.19$

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(B) The density of a crystal is given by the formula: $ho = \frac{n 	imes M}{N_A 	imes a^3} \, g \, cm^{-3}$.For a $bcc$ structure,the number of atoms per unit cell,$n = 2$.Given: Atomic mass $M = 100 \, g \, mol^{-1}$,edge length $a = 400 \, pm = 400 	imes 10^{-10} \, cm$,and Avogadro's number $N_A = 6.022 	imes 10^{23} \, mol^{-1}$.Substituting the values:$ho = \frac{2 	imes 100}{6.022 	imes 10^{23} 	imes (400 	imes 10^{-10})^3} \, g \, cm^{-3}$$ho = \frac{200}{6.022 	imes 10^{23} 	imes 64 	imes 10^{-24}} \, g \, cm^{-3}$$ho = \frac{200}{38.54} \approx 5.19 \, g \, cm^{-3}$.

An element with atomic mass $100$ has a $bcc$ structure and edge length $400 \, pm$. The density of the element is .............. $g \, cm^{-3}$.

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