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(A) The maximum efficiency of a heat engine is given by the Carnot efficiency formula: $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ and $T_2$ are the abso

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$1/2$

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(A) The maximum efficiency of a heat engine is given by the Carnot efficiency formula: $\eta = 1 - \frac{T_2}{T_1}$,where $T_1$ and $T_2$ are the absolute temperatures in Kelvin.Given: $T_1 = 727^{\circ}C = 727 + 273 = 1000 \ K$ and $T_2 = 227^{\circ}C = 227 + 273 = 500 \ K$.Substituting the values into the formula:$\eta = 1 - \frac{500}{1000} = 1 - 0.5 = 0.5 = 1/2$.

An engine is supposed to operate between two reservoirs at temperatures $727^{\circ}C$ and $227^{\circ}C$. The maximum possible efficiency of such an engine is:

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