(B) The current in an $LR$ circuit at time $t$ is given by the formula: $i = i_0(1 - e^{-Rt/L})$.Here, the maximum current $i_0 = V/R = 5 \, V / 5 \,

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

(B) The current in an $LR$ circuit at time $t$ is given by the formula: $i = i_0(1 - e^{-Rt/L})$.Here, the maximum current $i_0 = V/R = 5 \, V / 5 \, \Omega = 1 \, A$.The time constant $\tau = L/R = 10 \, H / 5 \, \Omega = 2 \, s$.Given $t = 2 \, s$, the current $i$ is:$i = 1 \times (1 - e^{-(5 \times 2)/10})$$i = 1 \times (1 - e^{-10/10})$$i = (1 - e^{-1}) \, A$.

Class 12 Physics Electromagnetic Induction R-L D.C. Circuit

Medium

An ideal coil of $10 \, H$ is joined in series with a resistance of $5 \, \Omega$ and a battery of $5 \, V$. $2 \, s$ after joining, the current flowing in the circuit in amperes will be:

A
$e^{-1}$
B
$(1 - e^{-1})$
C
$(1 - e)$
D
$e$

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Physics Questions

Chapter

Electromagnetic Induction

Subtopic

R-L D.C. Circuit

In an $L-R$ decay circuit,the initial current at $t = 0$ is $I$. The total charge that has flown through the resistor until the energy in the inductor has reduced to one-fourth of its initial value is:

View Solution

The ratio of time constants during growth and decay of current in the circuit is

Medium

View Solution

The current in the $2\, \Omega$ resistance shown in the figure is:
$(a)$ Just after the closing of the key.
$(b)$ $A$ long time after the closing of the key.

Medium

View Solution

For the given circuit,the current through the battery of $6\,V$ just after closing the switch $S$ will be $.......A$.

MediumJEE MAIN 2022

View Solution

Find $V_A - V_B$ in steady state. (in $, V$)

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

An ideal coil of $10 \, H$ is joined in series with a resistance of $5 \, \Omega$ and a battery of $5 \, V$. $2 \, s$ after joining, the current flowing in the circuit in amperes will be:

Similar Questions

In an $L-R$ decay circuit,the initial current at $t = 0$ is $I$. The total charge that has flown through the resistor until the energy in the inductor has reduced to one-fourth of its initial value is:

The ratio of time constants during growth and decay of current in the circuit is

The current in the $2\, \Omega$ resistance shown in the figure is:$(a)$ Just after the closing of the key.$(b)$ $A$ long time after the closing of the key.

For the given circuit,the current through the battery of $6\,V$ just after closing the switch $S$ will be $.......A$.

Find $V_A - V_B$ in steady state. (in $, V$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module

The current in the $2\, \Omega$ resistance shown in the figure is:
$(a)$ Just after the closing of the key.
$(b)$ $A$ long time after the closing of the key.