An ideal gas is compressed from 10 dm^3 to 1 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The work done during the compression of a gas at constant pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$. Here, $P_{ext} = 2 \ b

Vedclass · Accepted Answer

$1.8$

Vedclass · Answer

(C) The work done during the compression of a gas at constant pressure is given by the formula: $W = -P_{ext} 	imes \Delta V$. Here, $P_{ext} = 2 \ bar$, $V_1 = 10 \ dm^3$, and $V_2 = 1 \ dm^3$. $\Delta V = V_2 - V_1 = 1 \ dm^3 - 10 \ dm^3 = -9 \ dm^3$. $W = -2 \ bar 	imes (-9 \ dm^3) = +18 \ bar \ dm^3$. Since $1 \ bar \ dm^3 = 100 \ J$, then $18 \ bar \ dm^3 = 1800 \ J = 1.8 \ kJ$. Since the work is done on the gas, the value is positive.

An ideal gas is compressed from $10 \ dm^3$ to $1 \ dm^3$ at a constant pressure of $2 \ bar$. Calculate the work done on the gas during compression. (in $kJ$)

Similar Questions

Two moles of an ideal gas expand freely and isothermally from $5 \ dm^3$ to $50 \ dm^3$. What is the value of $\Delta H$?

Exothermic reactions occur in which of the following processes?

What is meant by standard state?

Which of the following is not true?

The number of extensive properties in the following list is: enthalpy,density,volume,internal energy,temperature.

Vedclass Test Series

Exam Paper Generator

Online Exam Module