An ideal gas is taken from point $A$ to the point $B,$ as shown in the $P-V$ diagram. The work done in the process is

  • A
    $({P_A} - {P_B})({V_B} - {V_A})$
  • B
    $\frac{1}{2}({P_B} - {P_A})({V_B} + {V_A})$
  • C
    $\frac{1}{2}({P_B} - {P_A})({V_B} - {V_A})$
  • D
    $\frac{1}{2}({P_B} + {P_A})({V_B} - {V_A})$

Explore More

Similar Questions

$A$ cyclic process $ABCD$ is shown in the given $P-V$ diagram. In the following answer, the one that represents the same process as in the $P-T$ diagram is:

Difficult
View Solution

The following figure shows two processes $A$ and $B$ for a gas. If $\Delta Q_A$ and $\Delta Q_B$ are the amounts of heat absorbed by the system in the two cases,and $\Delta U_A$ and $\Delta U_B$ are the changes in internal energies,respectively,then:

In the given $PV$ diagram,a system goes from state $P$ to state $Q$ along two different paths. Along path $1$,the system is given $1000 \ J$ of heat. The work done by the system along path $1$ is $100 \ J$ more than the work done along path $2$. How much heat is transferred along path $2$ (in $J$)?

Difficult
View Solution

Four curves $A, B, C$ and $D$ are drawn in the adjoining figure for a given amount of gas. The curves which represent adiabatic and isothermal changes are

$A$ system is taken through a cyclic process represented by a circle as shown. The heat absorbed by the system is

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo