An ideal gas undergoes a cyclic process as shown in the diagram. The net work done by the gas in the cycle is

  • A
    $12\, \text{litre-atm}$
  • B
    $24\, \text{J}$
  • C
    $24\, \text{litre-atm}$
  • D
    $-24\, \text{J}$

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An ideal gas is made to undergo the cyclic process shown in the figure below. Let $\Delta W$ depict the work done,$\Delta U$ be the change in internal energy of the gas,and $Q$ be the heat added to the gas. The signs of each of these three quantities for the whole cycle will be ($0$ refers to no change):

One mole of a monatomic ideal gas undergoes the process $A \rightarrow B$ in the given $p-V$ diagram. The specific heat capacity in the process is:

$3\, \text{moles}$ of an ideal monoatomic gas perform a cycle as shown in the figure. The gas temperatures in different states are: $T_1 = 400\, K$, $T_2 = 800\, K$, $T_3 = 2400\, K$ and $T_4 = 1200\, K$. The work done by the gas during the cycle is ...... $kJ$.

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One mole of a gas obeying the equation of state $P(V-b)=RT$ is made to expand from a state with coordinates $(P_{1}, V_{1})$ to a state with $(P_{2}, V_{2})$ along a process that is depicted by a straight line on a $P-V$ diagram. Then, the work done is given by

$A$ quantity of monoatomic gas undergoes a process in which pressure is changed linearly with volume. The pressure and volume are changed from initial value $(P_{o}, V_{o})$ to final value $(3 P_{o}, 3 V_{o})$. The heat absorbed by the gas during the process is (in $P_{o} V_{o}$)

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