An ideal heat engine has an efficiency $\eta$. The coefficient of performance of the engine when driven backward will be

  • A
    $1-\left(\frac{1}{\eta}\right)$
  • B
    $\eta-\left(\frac{1}{\eta}\right)$
  • C
    $\left(\frac{1}{\eta}\right)-1$
  • D
    $\frac{1}{1-\eta}$

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