An ideal mono-atomic gas of given mass is hea | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The heat supplied at constant pressure is given by $\Delta Q = n C_p \Delta T$.The increase in internal energy is given by $\Delta U = n C_v \Delt

Vedclass · Accepted Answer

$3/5$

Vedclass · Answer

(B) The heat supplied at constant pressure is given by $\Delta Q = n C_p \Delta T$.The increase in internal energy is given by $\Delta U = n C_v \Delta T$.The fraction of heat energy used to increase internal energy is $f = \frac{\Delta U}{\Delta Q} = \frac{n C_v \Delta T}{n C_p \Delta T} = \frac{C_v}{C_p}$.We know that the ratio of specific heats is $\gamma = \frac{C_p}{C_v}$, so $\frac{C_v}{C_p} = \frac{1}{\gamma}$.For a mono-atomic gas, the adiabatic index is $\gamma = 5/3$.Therefore, the fraction is $f = \frac{1}{5/3} = 3/5$.

An ideal mono-atomic gas of given mass is heated at constant pressure. In this process, the fraction of supplied heat energy used for the increase of the internal energy of the gas is

Similar Questions

$A$ mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) is kept at room temperature $\left(27^{\circ} C\right)$. The ratio of the specific heat of these gases at constant volume is:

Write the value of $\gamma$ for a polyatomic gas.

What is the relationship between the internal energy $U$ of an ideal gas and its pressure $P$ and volume $V$?

If $\gamma$ is the ratio of specific heats and $R$ is the universal gas constant,then the molar specific heat at constant volume $C_{V}$ is given by

The specific heat of a gas at constant pressure $(C_p)$ is more than that of the same gas at constant volume $(C_v)$ because

Vedclass Test Series

Exam Paper Generator

Online Exam Module