An ideal transformer converts $220 V$ $AC$ to $3.3 kV$ $AC$. It transmits the power of $4.4 kW$. If the primary coil has $600$ turns,then the alternating current in the secondary coil is
- A$\frac{1}{3} A$
- B$\frac{4}{3} A$
- C$\frac{5}{3} A$
- D$\frac{7}{3} A$
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