An increase in equivalent conductance of a strong electrolyte with dilution is mainly due to

Resistance of a conductivity cell (cell constant $129 \; m^{-1}$) filled with $74.5 \; ppm$ solution of $KCl$ is $100 \; \Omega$ (labelled as solution $1$). When the same cell is filled with $KCl$ solution of $149 \; ppm$,the resistance is $50 \; \Omega$ (labelled as solution $2$). The ratio of molar conductivity of solution $1$ and solution $2$ is i.e.,$\frac{\wedge_{1}}{\wedge_{2}} = x \times 10^{-3}$. The value of $x$ is (Nearest integer). Given,molar mass of $KCl$ is $74.5 \; g \; mol^{-1}$.

Calculate $\wedge_0$ of $CH_2ClCOOH$ if $\wedge_0$ for $HCl, KCl$ and $CH_2ClCOOK$ are $4.2, 1.5$ and $1.1 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.

At $25^o C$,the molar conductivities at infinite dilution of $NaOAc$ and $HCl$ in water are $91.0 \, S \, cm^2/mol$ and $426.2 \, S \, cm^2/mol$,respectively. What is the value to be added to calculate the molar conductivity of $HOAc$ at infinite dilution?

Kohlrausch's law states that at

If $l = \text{length}$,$R = \text{Resistance}$,and $A = \text{Area of cross-section}$,then which of the following relations is correct?