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(D) The formula for Bulk modulus $(B)$ is given by: $B = \frac{\Delta P}{-\Delta V / V}$.Rearranging for the change in pressure: $\Delta P = B 	imes

Vedclass · Accepted Answer

$84$

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(D) The formula for Bulk modulus $(B)$ is given by: $B = \frac{\Delta P}{-\Delta V / V}$.Rearranging for the change in pressure: $\Delta P = B 	imes \left( -\frac{\Delta V}{V} ight)$.Given that the volume decreases by $0.004\%$,the volumetric strain is $\left| \frac{\Delta V}{V} ight| = \frac{0.004}{100} = 4 	imes 10^{-5}$.The Bulk modulus $B = 2100\,MPa = 2100 	imes 10^6\,Pa = 2.1 	imes 10^9\,Pa$.Substituting the values: $\Delta P = (2.1 	imes 10^9\,Pa) 	imes (4 	imes 10^{-5})$.$\Delta P = 8.4 	imes 10^4\,Pa = 84 	imes 10^3\,Pa = 84\,kPa$.

The increase in pressure required to decrease the $200\,L$ volume of a liquid by $0.004\%$ in a container is ............ $kPa$. (Bulk modulus of the liquid $= 2100\,MPa$)

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