An inductance coil has a resistance of $80 \Omega$. When an $AC$ signal of frequency $480 \text{ Hz}$ is applied to the coil,the voltage leads the current by $45^{\circ}$. The inductance of the coil in henry is $\left[\sin 45^{\circ}=\cos 45^{\circ}=1 / \sqrt{2}\right]$
- A$\frac{1}{24 \pi}$
- B$\frac{\pi}{20}$
- C$\frac{\pi}{40}$
- D$\frac{1}{12 \pi}$
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