An insulator plate is passed between the plates of a capacitor. Then the displacement current

How are radio waves produced?

$AC$ voltage $V(t) = 20 \sin \omega t$ of frequency $50 \, Hz$ is applied to a parallel plate capacitor. The separation between the plates is $2 \, mm$ and the area is $1 \, m^2$. The amplitude of the oscillating displacement current for the applied $AC$ voltage is ...... $\mu A$.
[Take $\varepsilon_0 = 8.85 \times 10^{-12} \, F/m$]

$A$ parallel plate capacitor of area $60\, cm^2$ and separation $3\, mm$ is charged initially to $90\, \mu C$. If the medium between the plates becomes slightly conducting and the plate loses the charge at the rate of $2.5\times10^{-8}\, C/s$,what is the magnetic field between the plates?

An electromagnetic wave of frequency $100 \text{ MHz}$ propagates through a medium of conductivity $\sigma = 10 \text{ mho/m}$. The ratio of maximum conducting current density to maximum displacement current density is . . . . . . . $\left[ \text{Take } \frac{1}{4 \pi \epsilon_0} = 9 \times 10^9 \text{ Nm}^2/\text{C}^2 \right]$

Write inferences from Maxwell's equations.