An iron ball and a wooden ball of the same ra | vedclass

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(B) The time of descent $t$ for an object falling from a height $h$ under gravity is given by the kinematic equation $h = ut + \frac{1}{2}gt^2$. Since

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Exactly equal

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(B) The time of descent $t$ for an object falling from a height $h$ under gravity is given by the kinematic equation $h = ut + \frac{1}{2}gt^2$. Since the balls are released from rest,$u = 0$,so $h = \frac{1}{2}gt^2$.Solving for $t$,we get $t = \sqrt{\frac{2h}{g}}$.In a vacuum,there is no air resistance,and the only force acting on the objects is gravity. Since the time $t$ depends only on the height $h$ and the acceleration due to gravity $g$,and both are independent of the mass or material of the objects,both balls will take the same amount of time to reach the ground.Therefore,the time taken is exactly equal.

An iron ball and a wooden ball of the same radius are released from a height $h$ in vacuum. The time taken by both of them to reach the ground is

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