An iron bar of length L has a magnetic moment | vedclass

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(A) Let the pole strength of the original iron bar be $m$. The magnetic moment is given by $M = m L$.When the bar is bent at the middle,each arm has a

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$\frac{M}{2}$

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(A) Let the pole strength of the original iron bar be $m$. The magnetic moment is given by $M = m L$.When the bar is bent at the middle,each arm has a length of $L/2$.The new magnetic moment $M'$ is the product of the pole strength $m$ and the effective length (the distance between the two poles).The effective length $L'$ is the distance between the two ends of the bent bar. Since the two arms of length $L/2$ make an angle of $60^{\circ}$,the effective length forms the third side of an isosceles triangle with two sides of length $L/2$ and an included angle of $60^{\circ}$.This triangle is equilateral,so the effective length $L' = L/2$.The new magnetic moment is $M' = m L' = m (L/2) = M/2$.

An iron bar of length $L$ has a magnetic moment $M$. It is bent at the middle of its length such that the two arms make an angle of $60^{\circ}$ with each other. The magnetic moment of this new magnet is:

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