An isomer of C_5H_{12} on reaction with Br_2 | vedclass

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(D) $1$. The isomer of $C_5H_{12}$ that gives only one monobrominated product $C_5H_{11}Br$ upon reaction with $Br_2 / 	ext{light}$ is neopentane $(2

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$2,2-$dimethyl$-1-$nitropropane (structure shown)

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(D) $1$. The isomer of $C_5H_{12}$ that gives only one monobrominated product $C_5H_{11}Br$ upon reaction with $Br_2 / 	ext{light}$ is neopentane $(2,2-	ext{dimethylpropane})$. This is because all $12$ hydrogen atoms in neopentane are equivalent.$2$. Neopentane reacts with $Br_2 / 	ext{light}$ to form $1-	ext{bromo}-2,2-	ext{dimethylpropane}$ $(X)$.$3$. The reaction of a primary alkyl halide $(X)$ with $AgNO_2$ proceeds via an $S_N2$ mechanism,where the nucleophile is the nitrite ion $(NO_2^-)$. Since $AgNO_2$ is largely covalent,the nitrogen atom acts as the nucleophile,leading to the formation of a nitroalkane $(R-NO_2)$ as the major product.$4$. Therefore,the reaction of $1-	ext{bromo}-2,2-	ext{dimethylpropane}$ with $AgNO_2$ yields $2,2-	ext{dimethyl}-1-	ext{nitropropane}$ $(Y)$ as the major product.

An isomer of $C_5H_{12}$ on reaction with $Br_2 / \text{light}$ gave only one isomer $C_5H_{11}Br(X)$. Reaction of $X$ with $AgNO_2$ gave $Y$ as the major product. What is $Y$?

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