An object 1;cm tall is placed 4;cm in front o | vedclass

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(B) For an upright (erect) and enlarged image,a concave mirror must be used.Given: Object height $O = +1\;cm$,Image height $I = +3\;cm$,Object distanc

Vedclass · Accepted Answer

Concave mirror of radius of curvature $12\;cm$

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(B) For an upright (erect) and enlarged image,a concave mirror must be used.Given: Object height $O = +1\;cm$,Image height $I = +3\;cm$,Object distance $u = -4\;cm$.Using the magnification formula for a mirror: $m = \frac{I}{O} = \frac{f}{f - u}$.Substituting the values: $\frac{+3}{+1} = \frac{f}{f - (-4)}$.$3 = \frac{f}{f + 4} \Rightarrow 3f + 12 = f$.$2f = -12 \Rightarrow f = -6\;cm$.The radius of curvature $R = 2f = 2(-6) = -12\;cm$.The negative sign indicates a concave mirror with a radius of curvature of $12\;cm$.

An object $1\;cm$ tall is placed $4\;cm$ in front of a mirror. In order to produce an upright image of $3\;cm$ height,one needs a:

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