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(B) In simple harmonic motion $(SHM)$,the maximum velocity of an object is given by:$v_{\max} = A\omega$From this,we can express the amplitude $A$ as:

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$\omega v_{\max}$

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(B) In simple harmonic motion $(SHM)$,the maximum velocity of an object is given by:$v_{\max} = A\omega$From this,we can express the amplitude $A$ as:$A = \frac{v_{\max}}{\omega} \quad ...(i)$where $A$ is the amplitude and $\omega$ is the angular frequency.The maximum acceleration of an object performing $SHM$ is given by:$a_{\max} = \omega^2 A$Substituting the value of $A$ from equation $(i)$ into the expression for $a_{\max}$:$a_{\max} = \omega^2 \left( \frac{v_{\max}}{\omega} \right)$$a_{\max} = \omega v_{\max}$

An object is executing simple harmonic motion with an angular frequency $\omega$. If the maximum velocity is $v_{\max}$,then the maximum acceleration of the object is:

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