An object is fixed at the bottom of a vessel | vedclass

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(C) The object is at the bottom of the vessel,which is filled with water to a height of $10 \,cm$. The plane mirror is placed $7 \,cm$ above the water

Vedclass · Accepted Answer

$14.5$

Vedclass · Answer

(C) The object is at the bottom of the vessel,which is filled with water to a height of $10 \,cm$. The plane mirror is placed $7 \,cm$ above the water surface.Due to refraction at the water-air interface,the object at the bottom appears to be at a shallower depth.The apparent depth $d'$ is given by the formula:$d' = \frac{	ext{Real depth}}{n} = \frac{10 \,cm}{1.33} \approx 7.52 \,cm$.The total distance of the apparent position of the object from the mirror is the sum of the distance of the mirror from the water surface and the apparent depth of the object:$D = 7 \,cm + 7.52 \,cm = 14.52 \,cm$.Since a plane mirror forms an image at the same distance behind it as the object is in front of it,the distance of the image from the mirror is $14.52 \,cm$,which is approximately $14.5 \,cm$.

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