An object is placed at 10 text{ cm} in front | vedclass

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(A) For a concave mirror, the focal length $f = -15 	ext{ cm}$ and the object distance $u = -10 	ext{ cm}$.Using the mirror formula $\frac{1}{v} + \

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virtual, erect and magnified

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(A) For a concave mirror, the focal length $f = -15 	ext{ cm}$ and the object distance $u = -10 	ext{ cm}$.Using the mirror formula $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$:$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = \frac{1}{-15} - \frac{1}{-10} = -\frac{1}{15} + \frac{1}{10} = \frac{-2 + 3}{30} = \frac{1}{30}$.Thus, $v = +30 	ext{ cm}$.Since $v$ is positive, the image is formed behind the mirror, which means it is virtual and erect.The magnification $m = -\frac{v}{u} = -\frac{30}{-10} = +3$.Since the magnification $m$ is positive and $|m| > 1$, the image is virtual, erect, and magnified.

An object is placed at $10 \text{ cm}$ in front of a concave mirror of focal length $15 \text{ cm}$. The image formed will be . . . . . . .

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