An orbital with one angular node shows three maxima in its radial probability distribution curve, the orbital is

For a given azimuthal quantum number $(l)$,the total number of magnetic quantum numbers $(m)$ is given by:

The orbital occupied by an electron with quantum numbers $n = 4, l = 3, m = 0$ and $s = -\frac{1}{2}$ is called

The number of unpaired electrons in $Fe^{3+}$ $(Z = 26)$ is:

Arrange the following orbitals in increasing order of energy based on the given values of principal quantum number $(n)$ and azimuthal quantum number $(l)$:
$(1) n = 4, l = 1$
$(2) n = 4, l = 0$
$(3) n = 3, l = 1$
$(4) n = 3, l = 2$

What is the maximum number of electrons which can be accommodated in an atom in which the highest principal quantum number value is $4$?