An organic compound containing $C$,$H$,and $N$ gave the following analysis: $C = 40\%$,$H = 13.33\%$,and $N = 46.67\%$. Its empirical formula would be:

  • A
    $C_2H_7N_2$
  • B
    $CH_5N$
  • C
    $CH_4N$
  • D
    $C_2H_7N$

Explore More

Similar Questions

An organic compound containing $C$ and $H$ has $92.3 \%$ of carbon. Its empirical formula is:

What is the mass percent of oxygen in ethanol $(C_2H_5OH)$ (in $\%$)?

An organic compound on analysis gives the following data: $C = 57.82 \%$,$H = 3.6 \%$ and the rest is oxygen. Its vapour density is $83$. Calculate its molecular formula.

The empirical formula of a compound is $CH_{2}O$. $0.0835 \ mol$ of the compound contains $1.0 \ g$ of hydrogen. What is the molecular formula of the compound?

Difficult
View Solution

Calculate the percentage composition of element $P$ in ${H_3PO_4}$. (in $\%$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo