An organic compound contains carbon,hydrogen,and oxygen. Its elemental analysis gave $C = 38.71 \%$ and $H = 9.67 \%$. The empirical formula of the compound would be:

  • A
    $CHO$
  • B
    $CH_4O$
  • C
    $CH_3O$
  • D
    $CH_2O$

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$0.5 \ g$ of an organic compound on combustion gave $1.46 \ g$ of $CO_2$ and $0.9 \ g$ of $H_2O$. The percentage of carbon in the compound is $...........$ ($NEAREST$ $INTEGER$). [$GIVEN$: Molar mass in $g \ mol^{-1}$: $C: 12, H: 1, O: 16$]

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