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Question

(C) The combustion of an organic compound containing $C, H,$ and $N$ follows the stoichiometry: $C_xH_yN_z + (x + y/4) O_2 \rightarrow x CO_2 + (y/2)

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$C_6H_8N_2$

Vedclass · Answer

(C) The combustion of an organic compound containing $C, H,$ and $N$ follows the stoichiometry: $C_xH_yN_z + (x + y/4) O_2 \rightarrow x CO_2 + (y/2) H_2O + (z/2) N_2$ Given that $x = 6$ (moles of $CO_2$),$y/2 = 4$ (moles of $H_2O$),and $z/2 = 1$ (moles of $N_2$). From $x = 6$,we get $6$ carbon atoms. From $y/2 = 4$,we get $y = 8$ hydrogen atoms. From $z/2 = 1$,we get $z = 2$ nitrogen atoms. Thus,the empirical formula is $C_6H_8N_2$.

An organic compound is estimated through the Dumas method and is found to evolve $6$ moles of $CO_2$,$4$ moles of $H_2O$,and $1$ mole of nitrogen gas. The formula of the compound is

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