An organic compound of molecular formula C_4H | vedclass

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(A) The molecular formula $C_4H_{10}O$ corresponds to either an alcohol or an ether.Since the compound does not react with sodium metal,it cannot be a

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Ethoxyethane

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(A) The molecular formula $C_4H_{10}O$ corresponds to either an alcohol or an ether.Since the compound does not react with sodium metal,it cannot be an alcohol; therefore,it must be an ether.When an ether reacts with excess $HI$,it undergoes cleavage to form alkyl halides.The problem states that only one type of alkyl halide is formed,which implies that the ether must be symmetrical.Ethoxyethane $(C_2H_5-O-C_2H_5)$ is a symmetrical ether.The reaction is: $C_2H_5OC_2H_5 + 2HI 	o 2C_2H_5I + H_2O$.

An organic compound of molecular formula $C_4H_{10}O$ does not react with sodium. With excess of $HI$,it gives only one type of alkyl halide. The compound is

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