An organic compound with the molecular formul | vedclass

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(D) $1$. The molecular formula $C_6H_6O$ corresponds to the degree of unsaturation $U = 6 - \frac{6}{2} + 1 = 4$, which suggests an aromatic ring.$2$.

Vedclass · Accepted Answer

Phenol

Vedclass · Answer

(D) $1$. The molecular formula $C_6H_6O$ corresponds to the degree of unsaturation $U = 6 - \frac{6}{2} + 1 = 4$, which suggests an aromatic ring.$2$. The compound dissolves in $NaOH$, indicating it is acidic in nature.$3$. It gives a characteristic violet colour with neutral $FeCl_3$, which is a standard test for phenolic groups.$4$. It reacts with bromine water to form a tri-bromo derivative $(2,4,6-	ext{tribromophenol})$, which is characteristic of phenol due to the strong activating effect of the $-OH$ group.$5$. Therefore, the compound is phenol.

An organic compound with the molecular formula $C_6H_6O$ dissolves in $NaOH$, gives a characteristic colour with neutral $FeCl_3$ and on treatment with bromine water gives a tri-bromo derivative. Which is that compound among the following?

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