An oxide of an element contains 20 % oxygen b | vedclass

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Question

(C) Let the total weight of the oxide be $100 \ g$. Since the oxide contains $20 \%$ oxygen by weight,the weight of oxygen is $20 \ g$ and the weight

Vedclass · Accepted Answer

$32$

Vedclass · Answer

(C) Let the total weight of the oxide be $100 \ g$. Since the oxide contains $20 \%$ oxygen by weight,the weight of oxygen is $20 \ g$ and the weight of the element is $100 - 20 = 80 \ g$. The equivalent weight of oxygen is $8 \ g$. According to the law of equivalence,the number of gram equivalents of the element must be equal to the number of gram equivalents of oxygen. $\frac{	ext{Weight of element}}{	ext{Equivalent weight of element}} = \frac{	ext{Weight of oxygen}}{	ext{Equivalent weight of oxygen}}$ $\frac{80}{E} = \frac{20}{8}$ $E = \frac{80 	imes 8}{20} = 32$ Therefore,the equivalent weight of the element is $32$.

Isotope	$\%$ Natural Abundance	Molar Mass $(g/mol)$
$^{35}Cl$	$75.77$	$34.9689$
$^{37}Cl$	$24.23$	$36.9659$

An oxide of an element contains $20 \%$ oxygen by weight. Calculate the equivalent weight of the element.

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Isotope $\%$ Natural Abundance Molar Mass $(g/mol)$

$^{35}Cl$ $75.77$ $34.9689$

$^{37}Cl$ $24.23$ $36.9659$

(in $u$)

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