An unpolarised beam of intensity $I_{0}$ falls on a polaroid. The intensity of the emergent light is

Statement-$I$: On viewing the clear blue portion of the sky through a calcite crystal,the intensity of transmitted light varies as the crystal is rotated.
Statement-$II$: The light coming from the sky is polarized due to the scattering of sunlight by particles in the atmosphere. The scattering is largest for blue light.

When an unpolarized light of intensity $I_0$ is incident on a polarizing sheet,the intensity of light which does not get transmitted is

Unpolarized light of intensity $I$ is incident on a system of two polarizers,$A$ followed by $B$. The intensity of emergent light is $I/2$. If a third polarizer $C$ is placed between $A$ and $B$,the intensity of emergent light is reduced to $I/3$. The angle between the polarizers $A$ and $C$ is $\theta$. Then:

The pass-axes of two polarisers were kept such that the incident unpolarised beam of intensity $I_0$ gets completely blocked. Another polariser was introduced in between these two polarisers with its pass-axis at $60^{\circ}$ with respect to the pass-axis of the first one. The output intensity would then become

When unpolarized light of intensity $I_0$ is incident on a polarizing sheet,the intensity of light that does not pass through is: