Angle of deviation (delta) by a prism (refrac | vedclass

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(A) The refractive index of a prism is given by the formula:$\mu = \frac{\sin \left(\frac{A + \delta}{2}\right)}{\sin \left(\frac{A}{2}\right)}$For a

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$\delta = (\mu - 1)A$

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(A) The refractive index of a prism is given by the formula:$\mu = \frac{\sin \left(\frac{A + \delta}{2}ight)}{\sin \left(\frac{A}{2}ight)}$For a very thin prism,the angle of prism $A$ and the angle of deviation $\delta$ are very small. Therefore,we can use the approximation $\sin 	heta \approx 	heta$.Substituting this into the formula:$\mu \approx \frac{\frac{A + \delta}{2}}{\frac{A}{2}}$Simplifying the expression:$\mu = \frac{A + \delta}{A}$$\mu A = A + \delta$$\delta = \mu A - A$$\delta = (\mu - 1)A$Thus,the angle of deviation for a thin prism is given by $\delta = (\mu - 1)A$.

Angle of deviation $(\delta)$ by a prism (refractive index = $\mu$ and supposing the angle of prism $A$ to be small) can be given by

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