Aniline reacts with an excess of alkyl halide | vedclass

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Question

(C) When aniline $(C_6H_5NH_2)$ reacts with an excess of alkyl halide $(R-X)$,it undergoes successive alkylation.$1$. The primary amine $(C_6H_5NH_2)$

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Quaternary ammonium compound

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(C) When aniline $(C_6H_5NH_2)$ reacts with an excess of alkyl halide $(R-X)$,it undergoes successive alkylation.$1$. The primary amine $(C_6H_5NH_2)$ reacts to form a secondary amine $(C_6H_5NHR)$.$2$. The secondary amine reacts further to form a tertiary amine $(C_6H_5NR_2)$.$3$. Finally,the tertiary amine reacts with the excess alkyl halide to form a quaternary ammonium salt $([C_6H_5NR_3]^+X^-)$.Therefore,the final product is a quaternary ammonium compound.

Aniline reacts with an excess of alkyl halide to give:

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