Aniline reacts with excess Br_2 / H_2O to giv | vedclass

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(A) When aniline reacts with excess bromine water $(Br_2 / H_2O)$,the $-NH_2$ group strongly activates the benzene ring towards electrophilic substitu

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(A) When aniline reacts with excess bromine water $(Br_2 / H_2O)$,the $-NH_2$ group strongly activates the benzene ring towards electrophilic substitution. This results in the substitution of bromine atoms at all available ortho and para positions,yielding $2,4,6-$tribromoaniline as the major white precipitate product.

Aniline reacts with excess $Br_2 / H_2O$ to give the major product.

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