Anvils made of single crystals of diamond,wit | vedclass

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(B) The diameter of the cones at the narrow ends is $d = 0.50 \; mm = 0.50 	imes 10^{-3} \; m$.The radius is $r = \frac{d}{2} = 0.25 	imes 10^{-3} \

Vedclass · Accepted Answer

$2.55 	imes 10^{11} \; Pa$

Vedclass · Answer

(B) The diameter of the cones at the narrow ends is $d = 0.50 \; mm = 0.50 	imes 10^{-3} \; m$.The radius is $r = \frac{d}{2} = 0.25 	imes 10^{-3} \; m$.The compressional force applied is $F = 50,000 \; N$.The pressure $p$ at the tip of the anvil is given by the formula:$p = \frac{F}{A} = \frac{F}{\pi r^2}$Substituting the values:$p = \frac{50,000}{\pi (0.25 	imes 10^{-3})^2}$$p = \frac{50,000}{\pi (0.0625 	imes 10^{-6})}$$p = \frac{50,000}{0.19635 	imes 10^{-6}}$$p \approx 2.546 	imes 10^{11} \; Pa \approx 2.55 	imes 10^{11} \; Pa$.Therefore,the pressure at the tip of the anvil is $2.55 	imes 10^{11} \; Pa$.

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