Appropriate reducing agent for the following conversion is:
$CH_2=CH-CH_2-CHO \to CH_3-CH_2-CH_2-CH_2OH$

Assertion $(A)$: Propene on addition with hydrogen bromide in the presence of peroxide gives $1-$bromopropane as the major product.
Reason $(R)$: $1-$bromopropane is the major product because it is formed through the stable carbocation.
The correct answer is

$CH_3 - CH = CH_2 \xrightarrow[(2) CH_3CO_2T]{(1) THF : BD_3} (A)$; Product $(A)$ of the above reaction is

The reaction of $CH_3-CH=CH_2$ (propene) with $HI$ gives isopropyl iodide instead of $n$-propyl iodide because:

Ethene when treated with $Br_2$ in the presence of $CCl_4$,which compound is formed?

Identify the final product $Y$ in the following reaction sequence:
$CH_2=CH_2$ $\xrightarrow{O_2/Ag} X$ $\xrightarrow{473 \ K} Y$