The reaction of aqueous $NaOH$ with white $P_4$ is given by: $P_4 + NaOH (aq) \rightarrow PH_3 + X$. The compound $X$ is:

  • A
    $NaH_2PO_2$
  • B
    $NaHPO_4$
  • C
    $Na_2CO_3$
  • D
    $NaHCO_3$

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