The aqueous solution of $AlCl_3$ is:

The ionization constant of nitrous acid is $4.5 \times 10^{-4}$. Calculate the $pH$ of $0.04 \ M$ sodium nitrite solution and also its degree of hydrolysis.

The approximate $pH$ of $0.01 \ M \ NaHA$ is calculated by: ($K_{a_1} = 10^{-6}$ and $K_{a_2} = 10^{-8}$ are ionization constants of $H_2A$)

Which of the following has the lowest degree of hydrolysis?

On dilution,the $pH$ of $CH_3COONH_4$ solution:

The degree of hydrolysis of a $0.01 \ M$ ammonium acetate solution is = ........ [ $K_h = 3.175 \times 10^{-5}$ ]