Arrange S, P, As in order of increasing ionis | vedclass

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(C) The increasing order of ionization enthalpy is $As < S < P$. On moving from left to right in a period,the ionization energy generally increases. O

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$As < S < P$

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(C) The increasing order of ionization enthalpy is $As On moving from left to right in a period,the ionization energy generally increases. On moving down the group,the ionization energy decreases. $As$ is in the $4^{th}$ period,while $S$ and $P$ are in the $3^{rd}$ period,so $As$ has the lowest ionization energy. Between $S$ $(3p^4)$ and $P$ $(3p^3)$,$P$ has a stable half-filled $3p$ orbital,making it harder to remove an electron compared to $S$. Thus,the correct order is $As < S < P$.

Arrange $S, P, As$ in order of increasing ionisation energy.

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