Arrange the given amines in decreasing order | vedclass

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Question

(A) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$(I)$ Piperidine: The nitrogen atom is $sp^3

Vedclass · Accepted Answer

$I > II > III$

Vedclass · Answer

(A) The basicity of amines depends on the availability of the lone pair of electrons on the nitrogen atom.$(I)$ Piperidine: The nitrogen atom is $sp^3$ hybridized,and the lone pair is localized. It is a secondary aliphatic amine,making it the most basic.$(II)$ Pyridine: The nitrogen atom is $sp^2$ hybridized. The lone pair is in an $sp^2$ orbital,which is more electronegative than an $sp^3$ orbital,making the lone pair less available for donation compared to piperidine.$(III)$ Aniline: The lone pair on the nitrogen atom is involved in resonance with the benzene ring (delocalized),making it the least basic.Therefore,the decreasing order of basicity is $I > II > III$.

Arrange the given amines in decreasing order of their basicity.

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Which of the options correctly represents the basicity order for these compounds?

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